He generally shows most of the signs of the misinformation accounts:

  • Wants to repeatedly tell basically the same narrative and nothing else
  • Narrative is fundamentally false
  • Not interested in any kind of conversation or in learning that what he’s posting is backwards from the values he claims to profess

I also suspect that it’s not a coincidence that this is happening just as the Elon Musks of the world are ramping up attacks on Wikipedia, specially because it is a force for truth in the world that’s less corruptible than a lot of the others, and tends to fight back legally if someone tries to interfere with the free speech or safety of its editors.

Anyway, YSK. I reported him as misinformation, but who knows if that will lead to any result.

Edit: Number of people real salty that I’m talking about this: Lots

  • dx1@lemmy.world
    0·
    1 month ago

    Meanwhile, at .ml:

    Since Pi is infinite and non-repeating, would that mean any finite sequence of non-repeating numbers should appear somewhere in Pi?

    • PhilipTheBucket@ponder.catOP
      1·
      1 month ago

      That’s actually a really good way to illustrate what is wrong with lemmy.ml.

      On math stack exchange:

      Let me summarize the things that have been said which are true and add one more thing.

      1. 𝜋 is not known to have this property, but it is expected to be true.
      2. This property does not follow from the fact that the decimal expansion of 𝜋 is infinite and does not repeat.

      On lemmy.ml:

      0.101001000100001000001 . . .

      I’m infinite and non-repeating. Can you find a 2 in me?

      You can’t prove that there isn’t one somewhere

      Why couldn’t you?

      Because you’d need to search through an infinite number of digits (unless you have access to the original formula)

      And:

      Not just any all finite number sequence appear in pi

      And:

      Yes.

      And if you’re thinking of a compression algorithm, nope, pigeonhole principle.

      All heavily upvoted.